Physics

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A metal rod of length (L) moves with velocity (v), perpendicular to its length, in a magnetic field B, which is perpendicular to both the rod and its velocity. If the length of the rod is doubled, what happens to the electric field in the rod?

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    Since it is a conducting metal, there is no net E field. Negative charge accumulates at one end of the rod, while the rod moves, but there is also a magnetic force on electrons that opposes the field created by displaced electron charge.

    If a closed circuit were formed, so that electrons were free to move in a current loop, the EMF (E-field times length) would double if the length of the rod doubled. The E-field would stay the same. I believe the value would be B * (V/c), but am not sure.

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