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A projectile is fired at an angle of 60degree with the horizontal and with the initial velocity 80m/s calculate (a) the time of flight(b)time to reach maximum height(c)it range(d)the velocity of projection 2seconds after been fired

  • Physics -

    a)T=2u sin60/g=13.85s
    b)t=T/2=6.92s
    c)R=554.25m

  • Physics -

    For a, using g = 9.80 m/s^2, I get
    T = 2 u sin 60/g = 14.14 s. If I use g = 9.81 m/s^2, I get 14.12 s.

    This leads to slightly different answers to b) and c) than were obtained by vishesh

    c) Use
    R = u cos 60 * T

  • Physics -

    A projectile is fired from ground level with an initial velocity of 50m/s and an initial angle of 30degree. Assuming g= 9.8 m/s*2, find:
    (a) The projectile total time of flight.
    (b) The maximum height attained
    (c) The total horizontal traveled
    (d) The final horizontal and vertical velocities just before it hits the ground

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