college trig
posted by Jim .
I need to find the domain of the following function:
y=arcsin((x3)/(2x+1))
My math is a bit rusty after holidays...This is what I did: (I'll use <> for the sign of 'not equal')
> 2x+1<>0 <=> 2x<>1 <=> x <> 1/2
But i'm not sure about the rest! What I though of doing was this: the domain of arcsin(x) is [1,1], so I could write that for the given function, ((x3)/(2x+1)) is between 1 and 1... Not sure though...Help!
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