college chemistry
posted by sparkle .
The value of the equilibrium constant (Kp) as represented by the first chemical equation is 4.57 x 102 at 395 °C. Calculate the value of the equilibrium constant (Kp) for the second equation at the same temperature. Express answer in scientific notation.
Cl2CO(g) = CO(g)+Cl2(g)
CO(g)+Cl2(g) = Cl2CO(g)

The second equation is just the reverse of the first equation; therefore, the Kp for the second equation is the reciprocal of Kp for the first one given; i.e.,
Kp2 = (1/4.57 x 10^2) = ??