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Physics

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A car is traveling at 54.2 km/h on a flat highway. The acceleration of gravity is 9.81 m/s^2.
PART 1: If the coefficient of kinetic friction between the road and the tires on a rainy day is 0.131, what is the minimum distance needed for the car to stop? Answer in unitsof m.
PART 2: What is the stopping distance when the surface is dry and the coefficient of kinetic friction is 0.603? Answer in units of m.

  • Physics -

    Frictional resistance, F
    = -μ mg
    acceleration, a
    = F/m
    = -μg

    For distance S, use
    v²-u²=2aS
    where v=final velocity =0
    u=initial velocity = 54.2 km/h = 15.06 m/s
    Solve for S.

    1. μ=0.131
    u=54.2
    a=-0.131*9.8=-1.284 m/s²
    S=15.06²/(-2*1.284)
    =88.3m

    The same approach can be used for both cases.

    Post your answers for a check if you wish.

  • Physics -

    omg thx so much!!!!

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