algabra 2

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One side of a triangle is 4 cm longer than the shortest side and 2 cm shorter than the longest side. The perimeter is 38 cm. Find the dimensions of the triangle.

  • algabra 2 -

    x+x-2+x+4=38
    3x+2=38
    3x=36
    x=12
    12, 10, 16

  • algabra 2 -

    PT=sum of all sides
    38=x+(x-2)+(x+4)
    38=x+x-2+x+4
    38=x+x+x-2+4
    38=3x+2
    38-2=3x
    36=3x
    36/3=3x/3
    12=x
    one side is 12
    12-2=10
    the other side is 10
    12+4=16
    the last side is 16

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