Algebra 2

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Is this how you solve t(t+1)(t+2)=0, x^3+4x=4x^2, and 3r^2=4r-1?

t=0 or t= -1 or t=2
{0, -1, -2}

x=0 or x=2
{0,2(double root)}

r=3 or r=1

  • Algebra 2 -

    The first two are fine.

    The third one: 3r^2 - 4 + 1 = (3r-1)(r-1)

    Take it from there.

  • Algebra 2 -


    it was {1/3, 1} right

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