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The flywheel of a steam engine runs with a constant angular speed of 164 rev/min. When steam is shut off, the friction of the bearings and the air brings the wheel to rest in 1.6 h. I figured out the constant angular acceleration=1.71 rev/min2 but im not sure how to find:What is the magnitude of the tangential component of the linear acceleration of a particle that is located at a distance of 44 cm from the axis of rotation when the flywheel is turning at 82.0 rev/min
physics  bobpursley, Monday, September 27, 2010 at 7:29pm
linear acceleration=1.71/min^2, I certainly would change that to rad/sec^2
, time radius
tangential acceleration=angularacceleration*radius. Since angular acceleration is constant, it does not matter what angular velocity is.
physics  Anonymous, Tuesday, September 28, 2010 at 6:55pm
i did what you told me but it was incorrect, did i make a mistake:
1.71/min^2*(pi/30)=0.179rad/s/s
(0.179rad/s/s)*44cm=7.876cm/s/s
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