math
posted by Anonymous .
at 1p.m. two trains, traveling towards each other, leave from towns that are 312 km apart. one train averages at most 82 km/h and the other at most 74 km/h. what is the earliest time for them to meet?

when they meet they both will have travelled the same time after 1:00 pm
distance covered by faster train === x
distance covered by slower train == 312x
time = distance/rate
x/82= (312x)/74
solve for x
that will give you the distance, from there you can find the time
add that time to 1:00 pm
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