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at 1p.m. two trains, traveling towards each other, leave from towns that are 312 km apart. one train averages at most 82 km/h and the other at most 74 km/h. what is the earliest time for them to meet?

  • math -

    when they meet they both will have travelled the same time after 1:00 pm
    distance covered by faster train === x
    distance covered by slower train == 312-x
    time = distance/rate

    x/82= (312-x)/74
    solve for x

    that will give you the distance, from there you can find the time
    add that time to 1:00 pm

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