Math
posted by Amy~ .
For this inequality
3x^(2)  2x 1 > or equal 0
I get x=1 , x=1/3
would the solution set become
{x1 < x < 1/3}
I wasn't sure about the sign, if it should be greater than or equal to .

3x^2  2x  1 >= 0,
Factor using the A*C Method:
A * C = 3 * 1 = 3 = 1 * 3,
3x^2 + (x 3x)  1 >= 0,
(3x^2  3x) + (x  1) >= 0,
3x(x  1) + (x  1) >= 0,
(x  1) (3x + 1) >= 0,
x  1 >= 0,
x >= 1.
3x + 1 >= 0,
3x >= 1,
x >= 1/3.
Solution Set: x >= 1, and x >= 1/3.
This is not a compound inequality; therefore, your last step does
not apply.