geometry
posted by chandrasalon .
Express answer in exact form.
Find the area of the smaller segment whose chord is 8" long in a circle with an 8" radius

make a sketch and draw the sector.
Notice that if you take the segment away, you would be left with an equilateral triangle of sides 8, and of course the angle is 60°
The sector would be 1/6 of the area of the circle.
So find the area of the equilateral, and subtract that area from the area of the sector.
Let me know what you get. 
Find the radius of the circle whose equation is (x^2  10x + 25) + (y^2  16y + 64) = 16.
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