Math word problem

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The hypotenuse of a right triangle is 22 m long. The length of one leg is 10 m less than the other. Find the lengths of the legs.
I have so far
let one leg be x
the other leg will be x-10
x^2 +(x-10)^2=22^2
x^2+x^2-20x+100=484

  • Math word problem -

    carry on ...
    x^2+x^2-20x+100=484
    2x^2 - 20x - 384 = 0
    x^2 - 10x - 192 = 0
    I used the formula to solve for x

    x = 19.7309

    one side is 19.7309, the other 9.7309

  • Math word problem -

    x^2+x^2-20x+100=484

    --> 2x^2-20x-384=0

    --> x^2-10x-192=0

    Now apply quadratic formula.

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