Hello! I was wondering if I could get some help solving this problem? A car travels at a constant speed of 10.0 m/s along a straight highway that is inclined 6.0 degrees for 11.0 s. How high vertically does the car travel?
Assuming that he is going uphill,
Distance, d = speed*time=10 m/s * 11 s
slope, θ= 6°
grade = tan(6°)
Difference in elevation
=d*tan(θ)