Post a New Question


posted by .

A diver running 1.8m/s dives out horizontally from the edge of a vertical cliff and 3.0s later reaches the water below. How high was the cliff, and how far from its base did the diver hit the water?

  • AP Physics B -

    h = ½gt², since diver's initial vertical speed is 0
    h = 44 m

    x = vt
    x = 5.4 m

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

More Related Questions

Post a New Question