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Intrinsic - 5.5, 5.5, 5.2, 5.3, 4.7, 5.5, 5.2, 5.3, 4.7, 5.4, 6.2, 5.2, 5.3, 4.7, 5.4, 6.2, 5.2, 5.5, 5.2, 5.3, 4.7, 5.4, 6.2, 5.2, 5.6 Extrinsic6.8, 5.5, 4.6, 5.7,5.6, 5.5, 4.6, 5.7, 5.6, 5.6, 5.5, 4.6, 5.7, 5.6, 5.6, 5.5, 4.6, 5.5, 4.6, 5.7 5.6, 5.6, 5.5,4.6, 4.8 1. Perform a two-tailed hypothesis test on both the intrinsic and the extrinsic variable’s data, using a .05 significance level. 2. Begin by creating a null and an alternate statement. 3. Identify the significance level, the test statistic, and the critical value. State whether you are rejecting or failing to reject the null hypothesis statement

  • statistics -

    From your data:

    Ho: mean 1 = mean 2
    Ha: mean 1 ≠ mean 2

    P = .05

    Z = (mean1 - mean2)/standard error (SE) of difference between means

    SEdiff = √(SEmean1^2 + SEmean2^2)

    SEm = SD/√(n-1)

    Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion related to that Z score.

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