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An elevator starts from rest with a constant
upward acceleration and moves 1m in the first
1.9 s. A passenger in the elevator is holding a
5.3 kg bundle at the end of a vertical cord.
The acceleration of gravity is 9.8 m/s2 .
What is the tension in the cord as the elevator accelerates?
Answer in units of N.

  • Physics -

    Use the fact that it goes 1 m in 1.9 s to get the acceleration, a.

    (1/20 a t^2 = (1/2)a*(1s)^2 = 1.7 m
    a = 3.4 m/s^2

    The tension T in the cord minus the weight equals ma.

    T = m (g + a)

    m = 5.3 kg and g = 9.8 m/s^2

    Do the numbers.

  • Physics -


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