# Physics

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An elevator starts from rest with a constant
upward acceleration and moves 1m in the first
1.9 s. A passenger in the elevator is holding a
5.3 kg bundle at the end of a vertical cord.
The acceleration of gravity is 9.8 m/s2 .
What is the tension in the cord as the elevator accelerates?

• Physics -

Use the fact that it goes 1 m in 1.9 s to get the acceleration, a.

(1/20 a t^2 = (1/2)a*(1s)^2 = 1.7 m
a = 3.4 m/s^2

The tension T in the cord minus the weight equals ma.

T = m (g + a)

m = 5.3 kg and g = 9.8 m/s^2

Do the numbers.

• Physics -

69.96

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