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Betsy, a recent retiree, requires \$6,000 per year in extra income. She has \$70,000 to invest and can invest in B-rated bonds paying 17% per year or in a CD paying 7% per year. How much money should be invested in each to realize exactly \$6,000 in interest per year?

I do not know what to do for this.

For B-rated bonds at 17%, she gets
\$70000*0.17=\$11900 per year
In CD at 7%, she gets
\$70000*0.07=\$4900 per year.

If she invests \$x in B-rated bonds, and \$(70000-x) in CD, she should get \$6000, or
\$x*0.17+(70000-x)*0.07 = 6000

Solve for x

Would x be \$4,583.33?

From the equation x(o.17) + (70,000-x)(0.07) = 6,000
I got 0.17x + 4,900 -0.07x = 6,000 and then I subtracted 4,900 from 6,000 and I added 0.07 to 0.17 and got 0.24x. Is this correct?

6000-4900=1100 is correct, but

So x=4583.33 is not correct (it should be more than double 4583.)

The easiest way to check is to put x back in the equation and see if it comes out to be \$6000.

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