PreCalculus
posted by Melina .
Three numbers whose sum is 15 are in an arithmetic progression. The product of the 1st two numbers is 2 more than the 3rd. Find the three numbers.

Designate the three numbers, in order as x, y and z.
x<y<z
xy = z +2 or xy  2 = z
x + y + z = 15
x = 2, y = 5, z = 8