# Algebra

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The width of a rectangle is 3 yards less than its length. the perimeter is 130 yards. Find the length and width of the rectangle

• Algebra -

P = 2L + 2W

W = L - 3

P = 2L + 2(L - 3)
130 = 4L - 6
136 = 4L
34 = L

W = 31

• Algebra -

width --- x
length --- x-3

solve
2x + 2(x-3) = 130

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