ALGEBRA 2 URGENT! PLEASE HELP!

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Simplify


8(2^x-1)=64

  • ALGEBRA 2 URGENT! PLEASE HELP! -

    Since 8^2=64, set 2^x-1=2, 2^1=2 so x-1=1, x=?

  • ALGEBRA 2 URGENT! PLEASE HELP! -

    I'm assuming x-1 is the exponent.
    8 * 2^(x-1) = 64,
    2^3 * 2^(x-1) = 2^6,
    Add the exponents on the left side:
    3 + x - 1 = x + 2,
    2^(x+2) = 2^6,
    The exponent on both sides has the
    same base(2). Therefore,
    x + 2 = 6,
    x = 4.


    Check: substitute 4 for x in the given Eq:
    8 * 2^(4-1) =
    8 * 2^3 = 8 * 8 = 64.

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