Post a New Question

Calculus

posted by .

lim (2e^(x-5))-2
---------------
x-4
x->5

  • Calculus -

    lim as x approaches 5
    (2e^(x-5))-2/x-4

  • Calculus -

    stuck...

  • Calculus -

    plug in 5 for x and solve!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. calculus again

    Suppose lim x->0 {g(x)-g(0)} / x = 1. It follows necesarily that a. g is not defined at x=0 b. the limit of g(x) as x approaches equals 1 c.g is not continuous at x=0 d.g'(0) = 1 The answer is d, can someone please explain how?
  2. CALCULUS

    Evaluate each of the following. (a) lim x->0(e^x)-1-x/ x^2 (b) lim x->0 x-sinx/x^3 (c) lim x->infinity (In x)^2/x (d) lim x->0+ (sinx)In x (e) lim x->0+ (cos3x)^5/x (f) lim x->1+ ((1/x-1) -(1/In x))
  3. calculus

    f(x)= 3x+2, x<0 3, x=0 x^2+1, x>0 g(x)= -x+3, x<1 0, x=1 x^2, x>1 find a) lim x->0+ g(f(x)) b)lim x->0- g(f(x)) c) lim x->1+ f(g(x)) d)lim x->1- f(g(x)) I am trying to understand these. Help appreciated. Have …
  4. Calculus

    Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or - ∞. f(x) = { 2 - x if x ≤ 3 { -1 + 3x - x^2 if x > 3 a) lim 3+ f(x) x->3 b) lim 3- f(x) x->3 c) lim f(x) x->3 …
  5. Calculus

    Find the indicated limits. If the limit does not exist, so state, or use the symbol + ∞ or - ∞. f(x) = { 2 - x if x ≤ 3 { -1 + 3x - x^2 if x > 3 a) lim 3+ f(x) x->3 b) lim 3- f(x) x->3 c) lim f(x) x->3 …
  6. Calculus

    Show that limit as n approaches infinity of (1+x/n)^n=e^x for any x>0... Should i use the formula e= lim as x->0 (1+x)^(1/x) or e= lim as x->infinity (1+1/n)^n Am i able to substitute in x/n for x?
  7. Math(calculus)

    Evaluat d 4lowing1.lim x/|x| x-->0 2.lim x->1 sqrt(x^2+2- sqrt3)/x-1 3.lim n->~ f(n)=(1+1/n)^sqrtn 4. limx->0 f(x)= (12^x-3^x-4^x+1)/xtanx 5. Lim x->3 (x^n-3^n)^n/(n-3)^n
  8. Calculus

    uu) lim ln(1-x) as x->1- yy) lim (√(6-x)-2)/(√(3-x)-1) as x-> 2 zz) lim (1-(1/2)arctanx) as x->-∞ bbb) lim ln|1-x| as x->1 If these are hard to interpret with all the parentheses, you can plug them in …
  9. Calculus

    Find the following limits algebraically or explain why they don’t exist. lim x->0 sin5x/2x lim x->0 1-cosx/x lim x->7 |x-7|/x-7 lim x->7 (/x+2)-3/x-7 lim h->0 (2+h)^3-8/h lim t->0 1/t - 1/t^2+t
  10. Calculus

    Find the limit. lim 5-x/(x^2-25) x-->5 Here is the work I have so far: lim 5-x/(x^2-25) = lim 5-x/(x-5)(x+5) x-->5 x-->5 lim (1/x+5) = lim 1/10 x-->5 x-->5 I just wanted to double check with someone and see if the answer …

More Similar Questions

Post a New Question