Physics
posted by Anonymous .
This is a twodimensional kinematics question:
A particle's position coordinates (x,y) are (2m, 3m) at t=0; (6m, 7m) at t=2s, and (13m, 14m) at t=5s. Find the average velocity vector between t=0s and a) t=2s, b) t=5s.
I don't know how to find this without acceleration being given.

Physics 
drwls
You don't need to know the acceleration.
For average velocity, just divide the position change vector by the time interval.
Between t= 0 and 2s, the x position increases by 4 m and the y position increases by 4 m.
The average velocity components are
Vx = 2 and Vy = 2.
Do the 5 second case the same way.
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