Chemistry
posted by Anonymous .
How do you solve this equation? A piece of aluminum with a mass of 3.90g and a temperature of 99.3 degrees celcius is dropped into 10.0 g of a water at a temperature of 22.6 degrees celcius. What is the final temperature of the system?

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[masss Al x specific heat Al x (TfinalTinitial)] + [mass water x specific heat water x (TfinalTinitial)] = 0
Solve for Tfinal. 
(3.9)*(0.9025J)*(Tfinal99.3)+(10)*(4.184J)*(Tfinal22.6)=0
(3.51975J)*(Tfinal99.3)+(41.84J)*(Tfinal22.6)=0
45.35975JTfinal1295.095175=0
1295.095175/45.35975=28.6 degrees celsius
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