posted by Anonymous .
How do you solve this equation? A piece of aluminum with a mass of 3.90g and a temperature of 99.3 degrees celcius is dropped into 10.0 g of a water at a temperature of 22.6 degrees celcius. What is the final temperature of the system?
[masss Al x specific heat Al x (Tfinal-Tinitial)] + [mass water x specific heat water x (Tfinal-Tinitial)] = 0
Solve for Tfinal.
1295.095175/45.35975=28.6 degrees celsius