Physics
posted by G .
24. 0/3 points All Submissions Notes Question: Walker2 3.P.015.
Question part Points Submissions 1 2 3
0/1 0/1 0/1
0/7 3/7 2/7
Total 0/3 A vector A has a magnitude of 49.0 m and points in a direction 20.0° below the x axis. A second vector, B, has a magnitude of 70.0 m and points in a direction 41.0° above the x axis.
Find the magnitude and direction of the vector D.

I do not see how the vector D is defined. I have to assume that vector D is the sum of vectors A and B.
To find the resultant (sum) of vectors, you would sum the x and ycomponents by resolving the vectors in the xdirection (Pcos(θ)) and ydirection (Psin(θ)).
The magnitude of the resultant is
sqrt(SumX²+SumY²)
and the direction is obtained by
atan(SumY/SumX).
Pay attention to the quadrant of the angle by observing the signs of SumX and SumY.
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