physics
posted by demi .
A bird watcher meanders through the woods, walking 0.45 km due east, 0.60 km due south, and 2.70 km in a direction 37.0° north of west. The time required for this trip is 4.00 h.
(a) Determine the magnitude and direction (relative to due west) of the bird watcher's displacement. Use kilometers and hours for distance and time, respectively.
(b) Determine the magnitude and direction (relative to due west) of the bird watcher's average velocity.

n = North component = .6 + 2.7 sin 37
w = West component = .45 + 2.7 cos 37
magnitude^2 = n^2 + w^2
direction north of west = tan^1 (n/w)
ns = north speed = n/4
ws = west speed = w/4
now do the same thing for magnitude of velocity
the angle for velocity is the same as for displacement (top and bottom both divided by 4)
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