physics

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a car starting from rest is accelerated at 2m/s(square) for 10s, then moves at constant velocity for 20s and then decelerates at 1m/s(square), finally stops. how far does it travel during its trip?
please help me! I need in solution for that problem

  • physics -

    Stage 1, acceleration
    a = 2 m/s^2
    v = 0 + 2 * 10 = 20m/s
    x = 0 + 0*10 + .5 (2)(10^2) = 100 m

    Stage 2, starting with v = 20 and x = 100
    a = 0
    v = 20 + 0 * 20 = 20
    x = 100 + 20(20) +.5*0*20^2 = 500

    stage 3, starting with v = 20 and x = 500

    a = -1
    v = 20 -1(t) = 20 -t
    v = 0 at end so t = 20 for deacceleration
    x = 500 + 20(20) -.5(20)^2
    = 500 + 400 - 200
    = 700

  • physics -

    For this problem:
    Change in speed over change in time is acceleration...
    A car travels on a straight, level road. Starting from rest, the car is going 20 m/s at the end of 2.0 sec.
    (a) What is the acceleration of the car during the first 2.0 seconds of motion?
    In 7.0 more seconds, the car is going 40 m/s.
    (b) What is the car's acceleration for this period of time (during the 7 seconds)
    The car then slows to 19 m/s in 2.0 seconds.
    (c) What is the acceleration of the car during this period of time?
    (d) What is the overall average acceleration of the car for the total time?

  • physics -

    (a)80m

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