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How much energy is evolved during the reaction of 48.7 g of Al, according to the reaction below? Assume that there is excess Fe2O3.

Fe2O3(s) + 2 Al(s) → Al2O3(s) + 2 Fe(s), ΔH°rxn = -852 kJ

  • College Chem. -

    delta H rxn = -852 kJ.
    That is for 2*atomic mass Al in grams.
    You want to know for 48.7 g. Simple proportion.

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