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Assuming the density of a 5% acetic acid solution is 1.0 g/mL,determine the volume of the acetic acid solution necessary toneutralize 25.0 mL of 0.10M NaOH.


    L x M = moles NaOH used.
    moles acetic acid = moles NaOH
    g acetic acid = moles x molar mass.

    1 g/cc x #cc x 0.05 = grams acetic acid.
    Solve for #cc.
    Check my thinking. Check my work.

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