Math Word Problem
posted by MBK .
The length of a rectangle is twice the width. The area is 242 yd^2. Find the length and the width of the rectangle.
The width would be? The length would be?
I am not sure if I am to take 242 and sqrt it to give me 58,564 and then divide by 4 or what. I am lost with this.

L = 2W
L * W = 242
2W * W = 242
Solve for W, then L. 
So the L=242 and the W=60.5
Or am I way off base with this? 
Or would the L=484 and the W=242

no, work out PsyDAG's equation.
2W*W = 242
W^2 = 121
W = √121 = 11
so W = 11
L = 2W = 22
Check:
Area = 11*22 = 242 
6+6

The area of a rectangle is
99 ft2
, and the length of the rectangle is
7 ft
more than twice the width. Find the dimensions of the rectangle.