algebra
posted by peggy .
find the product of (x^23x+5)with the quotient of (21x^6 14x^57x^3)divide by 7x^3

I interpret your question as
(x^23x+5)(21x^6 14x^57x^3)/(7x^3)
= (x^23x+5)(3x^3  2x^2  1)
expanding this gives you 6 different terms starting with 3x^5 and ending with 5
I would leave it in factored form.
Reply if my interpretation is incorrect, seems like very little happened.
btw, 3x^2  2x^2  1
factors to (x+1)(x1)(3x+1)
but x^2  3x + 5 does not factor.
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