# algebra

posted by .

The length of a rectangular field is 18 m longer than the width. The field is enclosed with fencing and divided into two parts with a fence parallel to the shorter sides. If 216 m of fencing are required, what are the dimensions of the outside rectangle?

• algebra -

From your description, I am not sure that the fencing is around the whole perimeter of the field. If it is:

L = W + 18

2L + 2W = 216

2(W + 18) + 2W = 216

Solve for W, then put value in the first equation to solve for L. Check by inserting both values into the second equation.

• algebra -

A rectangular field is 3 yards longer than twice its width. If the perimeter is 156 yards, how wide is the field?

## Similar Questions

1. ### MATH

A rectangular field is to be enclosed with 1200 ft of fencing. If the length of the field is 40 ft longer than the width, then how long is the field?
2. ### algebra

The length of a rectangular field is 18 m longer than the width. If 216 m of fencing are required, what are the dimensions of the outside rectangle?
3. ### Algebra 2

A Rectangular Field is to be enclosed by a fence and divided into three parts by another fencer. Find the maximum area that can be enclosed and separated in this way with 500 meters of fencing.
4. ### Algebra 2

A Rectangular Field is to be enclosed by a fence and divided into three parts by another fencer. Find the maximum area that can be enclosed and separated i this way with 500 meters of fencing
5. ### math

the length of a rectangular field is 18 m longer than the width. the field is enclosed with fencing and divided into two parts with a fence parallel to the shoter sides. if 216 m of fencing are required to the shoter sides. if 216 …
6. ### Calculus 1

A rectangular field is enclosed by a fence and separated into two parts by a fence parallel to one of the sides. If 600 m of fencing is available, what should the dimensions be so that the area is a maximum?
7. ### precalculus

A rectangular field is to be enclosed by a fence and divided into three equal rectangular parts by two other fences. find the maximum area that can be enclosed and separated in this way with 1200m of fencing.
8. ### calculus (optimization)

a rectangular study area is to be enclosed by a fence and divided into two equal parts, with the fence running along the division parallel to one of the sides. if the total area is 384 square feet, find the dimensions of the study …
9. ### Calculus

A rectangular field is to be enclosed by a fence and divided into three lots by fences parallel to one of the sides. Find the dimensions of the largest field that can be enclosed with 800 feet of fencing. Help me please!!!!!!!!!!! …
10. ### Math

A rectangular field is to be enclosed with a 1130ft of fencing, if the length of the field is 45ft longer than the width. How long is the field?

More Similar Questions