Algebra

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I am working on Factoring the Trinomial and need help to solve this equation: t=3t^3+22t^2+8t

  • Algebra -

    t = 3t^3 + 22t^2 + 8t
    subtract t from both sides
    3t^3 + 22t^2 + 7t = 0

    t is common to each term
    t(3t^2 + 22t + 7) = 0
    So, t = 0 is one solution.
    Factor 3t^2 + 22t + 7 to get the other two solutions.

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