Post a New Question


posted by .

A stock solution's hypochlorite activity was determined as follows: . -
2.00g of liquid sodium hypochlorite (NaOCl) was weighed into a flask and diluted with 50mL deionized water.10mL of 10% sulfuric acid and 10mL of 10% potasssium iodide were added, followed by titration with 0.1N sodium thiosulfate (Na2S2O3) until colorless.
% sodium hypochlorite
= (mL Na2S2O3)(0.1N)(0.03722)/2.00gNaOCl X 100

[The factor 0.03722 was derived by multiplying molecular weight of NaOCl (74.45g/mol) by 0.001 (mL to L conversion) and dividing by 2(mols of thiosulfate per hypochlorite).]

Please explain why we need to multiply by 0.1N? Thanks.

  • chemistry -

    Break it down into steps.
    Step 1 is to calculate #mew.
    mL x N = number of milliequivalents.

    Step 2 convert #mew to grams.
    number of milliequivalents x milliequivalent weight = grams.

    Step 3 converts grams to percent
    (grams/weight sample) x 100 = percent.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question