Math
posted by Cynthia .
A tank in the shape of a cone has a diameter of 8 feet and a height of 10 feet.when there is water in the tank, th water is in the shape of a cone too. find the radius of the cone of water when the water is 2 feet high. Explain how you would solve it.

first, imagine the front view of the cone,, it should look like an inverted triangle,, then draw the content (the water  horizontal line),, note that if you draw a vertical line bisecting the inverted triangle, you actually form a right triangle,,
since you bisected it, get the radius: r= d/2 = 8/2 = 4 feet
then draw another horizontal line for which height is 2 feet,,
recall similar triangles,, you just have to do ration and proportion of the base and height,, therefore:
let x = radius when height is 2 feet
4/x=10/2
x= 4/5 or 0.8 feet
so there,, =)
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