posted by Crazy .
two helicopters flying at an altitude of 250 m are 2000m apart when they spot a life raft below. the raft is directly between the two helicopters. the angle of depression from one helicopter to the raft is 37 degrees. the angle of depression from the other helicopter is 49 degrees. both helicopters are flying 170 km/h. how long, to the nearest second, will it take the closer aircraft to reach the raft?
Sin49 = h/d1 = 250m/d1.
d1 = 250/Sin49 =331.3m = Distance of 1st helicopter.
Sin37 = h/d2 = 250/d2
d2 = 250/Sin37 = 415.4m = Distance of
d1 = r*t, t = d1/r =0.3313km / 170km
= 0.00195h = 0.00195h * 3600s/h =