The L and C State Building is 1,250 m tall. What is the angle od elevation of the top from a point on the ground 1,760 m from the base of the building?
tan A = OPPOSITE/ADJACENT = 1250/1760
To find the angle of elevation of the top of the L and C State Building from a point on the ground, we can use trigonometry. The angle of elevation is the angle between the horizontal line and the line of sight from the ground point to the top of the building.
Let's call the height of the building "h" and the distance from the ground point to the base of the building "d." In this case, h = 1,250 m and d = 1,760 m.
The tangent of the angle of elevation (θ) is defined as the ratio of the opposite side (h) to the adjacent side (d). In mathematical terms, this can be written as:
tan(θ) = h / d
To find the value of θ, we can rearrange the equation to solve for θ:
θ = arctan(h / d)
Now, substituting the values:
θ = arctan(1,250 / 1,760)
Using a calculator or trigonometric table, we can evaluate the arctan of the fraction:
θ ≈ 35.9 degrees (rounded to one decimal place)
Therefore, the angle of elevation of the top of the L and C State Building from the ground point is approximately 35.9 degrees.