algebra
posted by Gabby .
sqr root of 3a + 9(sqr root of 27a^3)

√27a^3 = 3a√3a
so
√(3a) + 9√(27a^3)
= √(3a) + 27a√(3a)
= √(3a)( 1 + 27a)
not much gained here, poor question if the instructions were to "simplify"
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