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If 5.05mL of 0.1000 M NaOH solution is needed to just neutralize excess acid after 20.00 mL of HCl was added to 1.00 g of an antacid, how many moles of acid can the antacid counteract per gram?

  • chemistry -

    You need to know the M of the HCl used.
    millimoles HCl used = 20.00 x ?M = xx.
    Excess is 5.05 mL x 0.1000 M NaOH = 0.505 mmoles excess acid.
    Initial mmoles - excess mmoles = mmoles antacid in the 1.00 g tablet. Then convert mmoles to moles.

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