# trigo

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4.2x2-1.2x6-0.018x5 divided by -6x4 =?

18y3-5y12-7y11 divided by 3/2y =?

• trigo -

-1.2X^6 - 0.018X^5 + 4.2X^2.
6X^2(-0.2X^4 -0.003X^3 +0.7)

• trigo -

Oops!! I missed a part of the problem
during my 1st response.

(-1.2X^6 -0.018X^5 +4.2X^2) / -6X^4
Divide each term by -6X^4:
2X^2 0.003X -0.7/X^2.
Remember to subtract the exponents when dividing.
negative exponent. So it was moved to the
denominator as a positive exponent

(18Y^3 -5Y^12 -7Y^11)/(3/2)Y.
Arrange exponents in decreasing order:
-5Y^12 - 7Y^

(-1.2X^6 - 0.018X^5 +4.2X^2)/-6X^4
Divide each term by -6X^4:
2X^2 + 0.003X - 0.7/X^2

(18Y^3 - 5Y^12 - 7Y^11)/(3/2)Y.
Arrange exponents in decreasing order:
(-5y^12 - 7y^11 + 18y^3)/(3/2)Y
Divide each term by y:
(-5Y^11 -7Y^10 + 18Y^2)/(3/2).
Multiply denominator and numerator
by 2/3:
2/3(-5Y^11 -7Y^^10 + 18Y^2.
Factor out Y^2:
(2/3)Y^2(-5Y^9 -7Y^8 + 18)

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