posted by anonymous .
Montreal’s Marathon building is 195m tall. From a point level with, and 48m away from, the base of the building, what is the angle of elevation of the top of the building, to the nearest degree?
The height of the building represents
the vertical leg of a rt. triangle, and
the hor dist. from the bottom is the hor. leg of the rt. triangle. The line
of sight from the end of the 48m line
to the top of building is the hyp. The
angle of elevation is the acute angle
between the hyp. and the hor. leg.
TanB = Y/X = 195/48 = 4.06, B = 76.2
deg. = angle of elevation.