I am down to 5 out of 49 problems that I can't figure out. Help is very much appreciated. Thanks !
c^2 +8c +15 =0
If you are down to 5, why did you post 8?
Are you supposed to factor this?
It looks like (c+5) is one of them.
For factoring, you have to find which two numbers add to the middle term and multiply to the last term. What two numbers add to 8 and multiply to 15? drwls started you off by saying 5 is one of them: (c+5).
A COUPLE OF THEM I COULD NOT CANCEL BUT POSTED A MESSAGE SAYING NEVERMIND. I ACTUALLY HAVE ONLY FOUR I COULDNT FIGURE OUT. THANKS ! (DIDNT KNOW CAPS LOCK WAS ON, =)
To solve the given equation c^2 + 8c + 15 = 0, you can use the quadratic formula:
c = (-b ± √(b^2 - 4ac)) / (2a)
Here, a, b, and c are the coefficients of the equation. In the given equation, we have:
a = 1, b = 8, and c = 15.
Substituting these values into the quadratic formula, we get:
c = (-(8) ± √((8)^2 - 4(1)(15))) / (2(1))
Simplifying further:
c = (-8 ± √(64 - 60)) / 2
c = (-8 ± √4) / 2
Now, we can calculate the two possible values of c:
c₁ = (-8 + √4) / 2 = (-8 + 2) / 2 = -6 / 2 = -3
c₂ = (-8 - √4) / 2 = (-8 - 2) / 2 = -10 / 2 = -5
Therefore, the solutions to the equation c^2 + 8c + 15 = 0 are c = -3 and c = -5.