# Chemistry

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What ratio is used to carry out each conversion?

a.mol CH4 to grams CH4
b.L CH4(g) to mol CH4(g)(at STP)
c.molecules CH4 to mol CH4

I honestly don't kno what it's asking me

I got 1 mol CH4/ 16(g) CH4 for a.
1 mol/22.4 L for b.
and 6.02 x 10^23 molecules/1 mol
but I don't think this is right, is it?

• Chemistry -

1 mol CH4 x (16 g CH4/1 mole CH4) = ?g CH4

L CH4 x (1 mole CH4/22.4 L) = ? moles CH4

#molecules CH4 x (1 mole/6.022 x 10^23 molecules) = ? moles CH4

The fraction (ratio) in parentheses is the ratio the problem is asking for. You did b right. Note that in my solutions for
a). mole cancels to leave g as the unit.
b). L cancels to leave moles as the unit.
c). # molecules cancel to leave moles as the unit.

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