# Chemistry

posted by .

how many mililiters of a 0.4 molar HCl solution are needed to react completely with 13 grams of zinc according to the following equation?

Equation.
2 HCl + 1 Zn -----> 1 ZnCl2 + 1 H2

• Chemistry -

1. Convert 13 g Zn to moles. moles = grams/molar mass.

2. Using the coefficients in the balanced equation, convert moles Zn to moles HCl.

3. Now convert moles HCl to volume.
M= moles/L. You know moles and M, calculate L and convert to mL.

## Similar Questions

1. ### science

How many grams of hydrochloric acid are required to react completely with 4.30g of zinc?
2. ### science

Posted by Josh on Saturday, March 17, 2007 at 10:58pm. How many grams of hydrochloric acid are required to react completely with 4.30g of zinc?
3. ### chemistry

how many mililiters of a 0.27 M HCl solution are needed to react completely with 2.7 g of zinc to form zinc (II) chloride?
4. ### Science

how many mililiters of a 0.4 molar HCl solution are needed to react completely with 13 grams of zinc according to the following equation?
5. ### DR.BOB HELP CHEMISTRY!

How many milliliters of a 0.3 molar HCl solution are needed to react completely with 8 grams of zinc according to the following equation?
6. ### Ap Chem

how many milliliters of a 0.9 molar HCl solution are needed to react completely with 12 grams of zinc according to the following equation 2HCl+ Zn yields ZnCl2+ H2
7. ### chemistry

How many milliliters of a 0.5 molar HCl solution are needed to react completely with 11 grams of zinc according to the following equation?
8. ### chemistry

How many milliliters of a 0.5 molar HCl solution are needed to react completely with 15 grams of zinc according to the following equation?
9. ### chemistry

How many milliliters of a 0.5 molar HCl solution are needed to react completely with 15 grams of zinc according to the following equation?
10. ### chemistry

The UNBALANCED equation is: Zn + HCl –] ZnCl2 + H2 How many milliliters of a 0.48 M HCl solution are needed to react completely with 7.4 g of zinc to form zinc(II) chloride?

More Similar Questions