Draw a bohr diagram of the protons and electrons in each of the following:
The ionic compounds lithium fluoride, LIF, and beryllium chloride, Becl2.
Do I draw these 2 compounds separately, and I'm unsure of how.
Yes, you draw individual IONS of Li^+ and F^-, for example, Here is a site that shows the orbits. For Li you would place two electrons in the first shell and the ion would have a 1+ charge; F would have 2e in the first shell and 8 in the second with a 1- charge. The question also wants you to show in the nucleus the number of protons.
I didn't post the link.
http://www.google.com/search?q=bohr+diagram&ie=utf-8&oe=utf-8&aq=t&rls=org.mozilla:en-US:official&client=firefox-a
To draw Bohr diagrams for the ionic compounds lithium fluoride (LiF) and beryllium chloride (BeCl2), you will need to draw the Bohr diagrams for each individual element and then combine them based on their ionic charges.
First, let's start with lithium fluoride (LiF):
Step 1: Draw the Bohr diagram for lithium (Li):
- Lithium (Li) has atomic number 3, meaning it has 3 protons in its nucleus.
- Draw three circles representing the energy levels around the nucleus.
- Place two electrons in the innermost circle and one electron in the second circle.
Step 2: Draw the Bohr diagram for fluorine (F):
- Fluorine (F) has atomic number 9, meaning it has 9 protons in its nucleus.
- Draw nine circles representing the energy levels around the nucleus.
- Place two electrons in the innermost circle, eight electrons in the next circle, and one electron in the third circle.
Step 3: Combine the Bohr diagrams based on their ionic charges:
- Lithium (Li) has a single valence electron, and fluorine (F) needs one more electron to fill its valence shell.
- The transfer of one electron from lithium to fluorine creates an ionic bond, resulting in Li+ and F-.
- In the final Bohr diagram, draw the Bohr diagram for lithium (Li) with no electrons in its outermost circle and fluorine (F) with eight electrons in its outermost circle.
Moving on to beryllium chloride (BeCl2):
Step 1: Draw the Bohr diagram for beryllium (Be):
- Beryllium (Be) has atomic number 4, meaning it has 4 protons in its nucleus.
- Draw four circles representing the energy levels around the nucleus.
- Place two electrons in the innermost circle and two electrons in the second circle.
Step 2: Draw the Bohr diagram for chlorine (Cl):
- Chlorine (Cl) has atomic number 17, meaning it has 17 protons in its nucleus.
- Draw seventeen circles representing the energy levels around the nucleus.
- Place two electrons in the innermost circle and eight electrons in the next circle. For the remaining seven electrons, place one in each of the remaining circles.
Step 3: Combine the Bohr diagrams based on their ionic charges:
- Beryllium (Be) has two valence electrons, and chlorine (Cl) needs one more electron to fill its valence shell.
- The transfer of two electrons from beryllium to two chlorine atoms creates an ionic bond, resulting in Be2+ and 2Cl-.
- In the final Bohr diagram, draw the Bohr diagram for beryllium (Be) with no electrons in its outermost circle and two separate Bohr diagrams for chlorine (Cl) with eight electrons in each of their outermost circles.
Remember that Bohr diagrams represent the electron configuration of atoms and ions, with each circle representing an energy level and the electrons placed within the circles according to the rules of filling the electron orbitals.