Grade 11th Physics

posted by .

This question is based upon differential calculus. Velocity of the particle is given by the equation:
v = (2t^2+5)cm/s. Find:-

(i) The change in velocity of the particle during the time interval t1 = 2s and t2 = 4s.
(ii) Average acceleration during the same interval.
(iii) Instantenous acceleartion at t = 4s.

Please SOLVE it!!!

  • Grade 11th Physics -

    (i) Use the formula you havebeen given to compute v at t = 4 and t = 2 s. Compute the change in v:
    v(4) - v(2) = 37 - 13 = ____ cm/s

    (ii) Divide the result of (i) by 2 s.

    (iii) Compute the formula for derivative of v(t).
    It is a(t) = dv/dt = 4t.
    That is the instantaneous acceleration. Evaluate it at t = 4s.

    Fill in the blanks. You could use the exercise.

  • Grade 11th Physics -

    Sir I want the answers so i could match my answers with yours

  • Grade 11th Physics -

    Then show your answers

  • Grade 11th Physics -

    Sir i'll solve tommorrow and show you. I hope you get back to this question tommorow

  • Grade 11th Physics -

    I have already shown you how to do the three problems. Each requires one step. I will be happy to verify that you have followed directions

  • Grade 11th Physics -

    Sir my teacher solved it!!!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Maths mst

    Question – 3: Consider a particle moving according to the velocity function, v(t) = 2a-3exp(-2t)+2/t+2,for t>0. (a) If the net distance,d,covered by the particle in the time interval,[0,3],is 20,find the value of a. What is the …
  2. Calc

    a partial moves along the x-axis so that its velocity at time t, for 0< = t = < 6, is given by a differentiable function v whose graph is shown above. The velocity is 0 at t=0, t=5, and the graph has horizontal tangents at t=4. …
  3. help math

    a partial moves along the x-axis so that its velocity at time t, for 0< = t = < 6, is given by a differentiable function v whose graph is shown above. The velocity is 0 at t=0, t=5, and the graph has horizontal tangents at t=4. …
  4. CALCULUS

    The displacement (in centimeters) of a particle moving back and forth along a straight line is given by the equation of motion s = 3sin(ðt) + 5cos(ðt), where t is measured in seconds. (Round all answers to the nearest hundredth.) …
  5. Calculus

    A particle moves along the x-axis with velocity v(t) = -(t-3)² + 5 for [0,6]. a) Find the average velocity of this particle during the interval [0,6]. b) Find a time t* ∈ [0,6] such that the velocity at time t* is equal to the …
  6. Calculus

    At time t >or= to 0, the position of a particle moving along the x-axis is given by x(t)= (t^3/3)+2t+2. For what value of t in the interval [0,3] will the instantaneous velocity of the particle equal the average velocity of the …
  7. calculus

    5. A particle moves along the y – axis with velocity given by v(t)=tsine(t^2) for t>=0 . a. In which direction (up or down) is the particle moving at time t = 1.5?
  8. Calculus

    The displacement (in meters) of a particle moving in a straight line is given by the equation of motion s = 5/t2, where t is measured in seconds. Find the velocity of the particle at times t = a, t = 1, t = 2, and t = 3. (a) Find the …
  9. Calculus

    The displacement (in meters) of a particle moving in a straight line is given by s=2t^3 where is measured in seconds. Find the average velocity of the particle over the time interval [10,13]. the average velocity is 798 What is the …
  10. Calculus

    The Question: A particle moves along the X-axis so that at time t > or equal to 0 its position is given by x(t) = cos(√t). What is the velocity of the particle at the first instance the particle is at the origin?

More Similar Questions