algebra
posted by Jimmy .
solve te compound inequality
6 > 5x + 5 or 9 <  3x + 4

Simplify both inequalities.
6 > 5x + 5
1 > 5x
5x > 1
x > 0.2
9 < 3x + 4
5 < 3x
3x < 5
x < 5/3
Final answer:
No solution
If x > 0.2, it cannot be also less than 5/3 
rewrite as
5x > 1 OR 3x < 5
x > 1/5 OR x < 5/3
On a number line, draw a small open circle around 5/3 with an arrow on a line going to the left, and a small open circle around 1/5 with an arrow going to the right.
In other words, the only numbers that will NOT work are between 5/3 and 1/5 inclusive.
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