lisa left home in a car that was traveling at the rate of 48 km/hr. she walked home at the rate of 6 km/hr. the round trip took 1.5 how far did lisa ride?
One of the best ways to do these is by using a "chart"
on the top: distance --- rate --- time
one the side: the two cases, in this problem: by car , walking
....... dist........rate....time
car ...48t ...... 48 ...... t
walk 6(1.5-t) .. 6 ..... (1.5-t)
So where does the equality come in ????
Ahhh, their distances are the same!
so solve
48t = 6(1.5-t)
( I get t = 1/6 and
distance = 48(1/6) = 8 )
thank you reiny^_^
To find how far Lisa rode, we need to calculate the distance for each part of the trip separately and then add them together.
Let's first find the distance Lisa traveled by car. We know that the car was traveling at a rate of 48 km/hr. To calculate distance, we can use the formula:
Distance = Speed × Time
The time Lisa spent driving is not given, but we can find it using the information given. We're told that the round trip took 1.5 hours and she walked at 6 km/hr. Therefore, the time Lisa spent walking can be calculated as:
Time walking = Distance walking / Speed walking
Since the distance Lisa traveled walking is not given, we can assume it is the same as the distance she traveled by car. Let's call this distance "d".
Time walking = d / 6 km/hr
Now, the total time of the trip is given as 1.5 hours. So we can write the equation:
Time driving + Time walking = 1.5 hours
(d / 48 km/hr) + (d / 6 km/hr) = 1.5
Now, let's solve this equation to find the value of "d" (distance):
(d / 48) + (d / 6) = 1.5
First, let's find the common denominator:
(d / 48) + (8d / 48) = 1.5
Now add the fractions:
(9d / 48) = 1.5
Divide both sides of the equation by 9:
d / 48 = 1.5 / 9
d / 48 = 0.16667
Now, multiply both sides by 48 to isolate the "d":
d = 48 * 0.16667
d = 8 km
Therefore, Lisa rode a distance of 8 kilometers.