calculus
posted by theophilus .
Find an equation of the tangent to the curve f(x) = 2x^2  2x + 1 that has slope 2.

f' = slope = 4 x 2
so
4x2 = 2
4 x = 4
x = 1
if x = 1 then
y = 2 2 + 1 = 1
so tangent at point (1,1) and m = 2
1 = 2 (1) + b
b = 1
so
y = 2 x  1
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