Post a New Question


posted by .

An astronaut on a distant planet wants to determine its acceleration due to gravity. The astronaut throws a rock straight up with a velocity of +13 m/s and measures a time of 20.5 s before the rock returns to his hand. What is the acceleration (magnitude and direction) due to gravity on this planet? (Indicate direction by the sign of the acceleration.)

  • physics -

    time rising = 20.5/2 = 10.25 seconds
    v = Vi + g t
    at top v = 0
    0 = 13 + g (10.25)
    since I chose acceleration up, g will be a negative acceleration.

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question