Consider the following equation:

N2O4(g)+ 2NO2(g) Kc= 5.8 x 10^-3

If the initial concentration of N2O4(g)= 0.040 M and the initial concentration of NO2(g) is 0 M, what is the equilibrium of concentration of N2O4(g)?

Did you make a typo, typing + instead of -->

Yes, I meant to right -->...I apologize for typing the question incorrectly.

If so, then

N2O4 ==> 2NO2

Set up ICE chart.
initial:
N2O4 = 0.040
NO2 = O

change:
NO2 = 2x
N2O4 = -x

equilibrium:
NO2 = 2x
N2O4 = 0.040-x

Set up Keq expression of
Keq = (NO2)^2/(N2O4), plug in the equilibrium values from above and solve for x. Finally, 0.040-x will be the N2O4 at equilibrium.

To determine the equilibrium concentration of N2O4(g) in this reaction, you can use the given equilibrium constant (Kc) along with the initial concentrations of the reactants.

First, let's assign variables to the initial concentrations and the equilibrium concentrations:

Initial concentration of N2O4(g) = [N2O4]0 = 0.040 M
Initial concentration of NO2(g) = [NO2]0 = 0 M

Let's assume that the equilibrium concentration of N2O4(g) is x M.

The balanced equation for the reaction is:

N2O4(g) + 2NO2(g) ⇌ 2NO2(g)

Using the stoichiometry of the balanced equation, we can express the equilibrium concentrations of the reactants and the product:

[N2O4] = [N2O4]0 - x
[NO2] = [NO2]0 + 2x

Substituting the given values, we have:

[N2O4] = 0.040 - x
[NO2] = 0 + 2x

Now, we can substitute these expressions into the equation for the equilibrium constant (Kc):

Kc = [NO2]^2 / [N2O4]
5.8 x 10^-3 = (0 + 2x)^2 / (0.040 - x)

Simplifying this equation, we get:

5.8 x 10^-3 = 4x^2 / (0.040 - x)

Now, we rearrange this equation to solve for x, the equilibrium concentration of N2O4(g).

4x^2 = 5.8 x 10^-3 * (0.040 - x)
4x^2 = 2.32 x 10^-4 - 5.8 x 10^-3 * x
4x^2 + 5.8 x 10^-3 * x - 2.32 x 10^-4 = 0

This is a quadratic equation. By solving this equation, you will find the equilibrium concentration of N2O4(g). You can use various methods to solve it, such as factoring, completing the square, or using the quadratic formula.

Once you find the value of x, you can substitute it back into the expression [N2O4] = 0.040 - x to find the equilibrium concentration of N2O4(g).